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Write the slope-intercept form of the equation of the line that passes through the point (4,3) and is parallel to y =
A Oy - - 2
B.Oy=-
C
D.Oy - 2x + 4

User Matei
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Final answer:

The slope-intercept form of the equation of a line parallel to y = -2x + 4 that passes through the point (4, 3) is y = -2x + 11.

Step-by-step explanation:

The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept. To find the equation of the line that is parallel to y = -2x + 4, we need to find the slope of the given line. Since the line is parallel, it will have the same slope. Therefore, the slope is -2.

Now we can use the point-slope form of a linear equation to determine the equation of the line passing through the point (4, 3) with slope -2:

y - y1 = m(x - x1)

Substituting the values, we get:

y - 3 = -2(x - 4)

y - 3 = -2x + 8

y = -2x + 8 + 3

y = -2x + 11

Therefore, the equation of the line that passes through the point (4, 3) and is parallel to y = -2x + 4 is y = -2x + 11.

User Rkaartikeyan
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