Final answer:
In the reaction between methane and oxygen to form water vapor and carbon dioxide, twice the volume of water vapor is produced relative to the methane volume consumed. So, for 2.15 m³ of methane, 4.30 m³ of water vapor would be created.
Step-by-step explanation:
The student's question pertains to the chemical reaction between methane gas (CH₄) and oxygen gas (O₂) to produce water vapor (H₂O) and carbon dioxide gas (CO₂).
According to the balanced chemical equation for this reaction, which is CH₄ + 2O₂ → CO₂ + 2H₂O, one mole of methane reacts with two moles of oxygen to produce one mole of carbon dioxide and two moles of water.
Given that the volume ratio of gases reacting at the same temperature and pressure is the same as the mole ratio according to Avogadro's Law, if 2.15 m³ of methane is consumed, exactly twice that volume of water vapor would be produced because the reaction produces two moles of water for every one mole of methane consumed. Therefore, 2.15 m³ of methane would yield 4.30 m³ of water vapor, rounded to three significant digits.