Question

Mr. Samalley is standing at the attendance office talking to Mr. Brackeet. He starts to run down a hall, accelerating at a rate of 1 m/s², running for 7 seconds. How far did he get?

Answer 1

Mr. Samalley covered a distance of 24.5 meters while running down the hall for 7 seconds with an acceleration of 1 m/s².

Step-by-step explanation:

To determine how far Mr. Samalley got, we can use the formula for distance covered under constant acceleration from rest:

d = ut + ½ at²

Where:

d is the distance traveled,

u is the initial velocity (which is 0 m/s since he starts from rest),

t is the time,

a is the acceleration.

Substituting the given values into the equation:

d = 0 m/s × 7 s + ½ × 1 m/s² × (7 s)²

d = 0 + ½ × 1 × 49

d = 0.5 × 49

d = 24.5 meters

Hence, Mr. Samalley covered a distance of 24.5 meters while running down the hall.