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A bird accelerates at a rate of 2.0 m/s from a velocity of 3.0 m/s to 11.0 m/s. How long does this take to

happen?

1 Answer

4 votes

Final answer:

It takes 4.0 seconds for a bird to accelerate from 3.0 m/s to 11.0 m/s at an acceleration rate of 2.0 m/s² by using the kinematic equation t = (v - u) / a.

Step-by-step explanation:

To determine how long it takes for a bird to accelerate from 3.0 m/s to 11.0 m/s at an acceleration rate of 2.0 m/s², we can use the basic kinematics equation for constant acceleration, which states:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. By reorganizing the formula to solve for time (t), we get:

t = (v - u) / a

Given the values v = 11.0 m/s, u = 3.0 m/s, and a = 2.0 m/s², we can calculate the time as:

t = (11.0 m/s - 3.0 m/s) / 2.0 m/s²

This equals 4.0 seconds.

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