Final answer:
To find the equation of a line parallel to y = 3x + 3 and passing through (2,12), we need to determine the slope of the given line and use it to construct the equation of the new line.
Step-by-step explanation:
To find the equation of a line parallel to y = 3x + 3 and passing through (2,12) in slope-intercept form, we need to determine the slope of the given line and use it to construct the equation of the new line.
The given line has a slope of 3, which means any line parallel to it will also have a slope of 3. Therefore, the slope of the new line is 3.
Using the slope-intercept form y = mx + b, where m is the slope and b is the y-intercept, we can substitute the slope and the coordinate (2,12) to find the equation. Since the line passes through (2,12), we have 12 = 3(2) + b. Solving for b, we get b = 6.
Therefore, the equation of the parallel line in slope-intercept form is y = 3x + 6.