Question

What slope would make the linesPerpendicular? Y= -1/6x -3 Y= [?]x + 1

Answer 1

Given the equation of the line in slope-intercept form:

`y=mx+b`

where 'm' defines the slope of the line, we can find the perpendicular slope using the following expression:

`m_p=-(1)/(m)`

In this case, we have the following equation of the line:

`y=-(1)/(6)x-3`

notice that the slope is m = -1/6. Then, using the expression for the perpendicular slope, we have:

`\begin{gathered} m_p=-(1)/(-(1)/(6))=6 \\ m_p=6 \end{gathered}`

therefore, the equation of the line that is perpendicular to y = -1/6x - 3 is:

`y=6x+1`