142k views
2 votes
100.0 ml of 4.0 oC water is heated until its temperature is 37 oC. If the specific heat of water is 4.18 J/g°C. Calculate the amount of heat energy required to cause this rise in temperature.

(a) 418 J
(b) 1254 J
(c) 1096 J
(d) 8376 J

1 Answer

4 votes

Final answer:

The heat energy required is calculated using the formula q = mcΔT, where m is 100.0 g (from 100.0 ml of water) and ΔT is 33 °C (the temperature increase from 4.0 °C to 37 °C). With a specific heat capacity of 4.18 J/g°C for water, the required energy is 13794 J, which does not match any of the given answer options.

Step-by-step explanation:

To calculate the amount of heat energy required to raise the temperature of 100.0 ml of water from 4.0 °C to 37 °C, we can use the formula for heat transfer: q = mcΔT, where q is the heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. Since the specific heat of water is 4.18 J/g°C and the density of water is approximately 1 g/ml, the mass of 100.0 ml of water is 100.0 g. Therefore, the calculation is
q = (100.0 g) × (4.18 J/g°C) × (37 °C - 4.0 °C)

q = 100.0 g × 4.18 J/g°C × 33 °C

q = 13794 J

However, options (a) through (d) do not match this result, which implies there might be an error in the answer choices or a misinterpretation of the question.

User LuckyStrike
by
7.7k points