Final answer:
To calculate the deceleration time for a car going from 75 mph to a complete stop with an acceleration of -98 miles per hour squared, we convert the given units to seconds and use the kinematic equation v = u + at. We find the deceleration time to be approximately 0.765 seconds.
Step-by-step explanation:
To determine how long it took for the car to decelerate to a complete stop from a speed of 75 miles per hour with a deceleration of -98 miles per hour squared, we can use the kinematic equation that relates velocity, acceleration, and time:
v = u + at
Where v is the final velocity (0, since the car stops), u is the initial velocity (75 mph), a is the acceleration (-98 mph²), and t is the time.
Firstly, let's convert the speed to miles per second by dividing by 3600 (the number of seconds in an hour):
75 mph / 3600 = 0.02083 miles per second
Similarly, we convert the acceleration:
-98 mph² / 3600 = -0.02722 miles per second squared
Now we substitute these values into our equation and solve for t:
0 = 0.02083 + (-0.02722)t
t = 0.02083 / 0.02722
t ≈ 0.765 seconds
Thus, the deceleration time for the car is approximately 0.765 seconds.