Question

A spaceship traveling at a velocity of 838 m/s accelerates at a rate of 59.7 m/s? What is the rocket's velocity after it accelerates for 36.8 seconds?

A) v(r) = 878.36m/s
B) v(r) = 1013.76m/s
C) v(r) = 912.56m/s
D) v(r) = 959.6m/s

Answer 1

The rocket's velocity after accelerating for 36.8 seconds is 1013.76 m/s.

The correct answer is B) v(r) = 1013.76m/s

Step-by-step explanation:

To find the rocket's velocity after it accelerates, we can use the equation v = u + at, where v is the final veolcity, u is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity is 838 m/s, the acceleration is 59.7 m/s², and the time is 36.8 seconds. Plugging these values into the equation, we get v = 838 + (59.7 * 36.8) = 1013.76 m/s. Therefore, the rocket's velocity after it accelerates for 36.8 seconds is 1013.76 m/s.