Question

A 7.10 L sample of gas has a pressure of 1.33 atm and a temperature of 91 degrees Celsius. The sample is allowed to expand to a volume of 9.82 L and is cooled to 37 degrees Celsius. Calculate the new pressure of the gas, assuming that no gas escaped during the experiment.

A) 1.00 atm
B) 1.42 atm
C) 1.76 atm
D) 2.13 atm

Answer 1

To calculate the new pressure of the gas, use the combined gas law equation with given values for initial pressure, volume, and temperature, as well as final volume and temperature. The new pressure of the gas is 2.13 atm.

Step-by-step explanation:

To calculate the new pressure of the gas, we can use the combined gas law equation:

P1 x V1 / T1 = P2 x V2 / T2

Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (unknown)
V2 = final volume
T2 = final temperature

Plugging in the given values:
P1 = 1.33 atm
V1 = 7.10 L
T1 = 91°C + 273.15 = 364.15 K
V2 = 9.82 L
T2 = 37°C + 273.15 = 310.15 K

Solving for P2:
P2 = (P1 x V1 x T2) / (V2 x T1) = (1.33 atm x 7.10 L x 310.15 K) / (9.82 L x 364.15 K) = 2.13 atm

The new pressure of the gas is therefore 2.13 atm.