Final answer:
The value of the expression (p+q)^0 + 1^p + q is 2 + q, using basic exponential rules and assuming that p and q do not have values that change the given expression.
Step-by-step explanation:
The student is asking to find the value of the expression: (p+q)^0 + 1^p + q. Recall the exponential rules: any nonzero number raised to the zero power is 1, and any number raised to the first power is the number itself. Therefore, (p+q)^0 is 1 because of the zero exponent, and 1^p is 1 since any number raised to any power is 1. Adding these together with q, we get 1 + 1 + q.
To address part of the provided information relating to probabilities, if p and q represent probabilities, by definition, p+q=1 for discrete probabilities that encompass all possible outcomes. This is not directly applicable to the calculation of the expression above, unless p and q were specified as such probabilities, but it's useful background information.
The value of the expression is thus 2 + q. Without the specific value of q, this is the most simplification that can be done.