Question

An object is launched with a vertical velocity of 44.3 m/s upward, and a horizontal velocity of 12 m/s. What is the maximum height reached by the object?

A)150 m
B)15 m
C)50 m
D)100m

Answer 1

The problem can be solved using the equation for maximum height in vertical motion, which yields a maximum height of approximately 100 meters when calculated with the given initial vertical velocity of 44.3 m/s. The answer is option D) 100 m.

Step-by-step explanation:

The maximum height reached by an object thrown vertically with an initial speed can be determined using the kinematic equation for vertical motion under constant acceleration (gravity):

h = (v^2) / (2g),

where h is the maximum height, v is the initial vertical velocity, and g is the acceleration due to gravity (9.8 m/s2, downward).

In the problem provided, the vertical velocity is 44.3 m/s. Using the formula, we get:

h = (44.3 m/s)^2 / (2 * 9.8 m/s2),

which calculates to a maximum height of approximately 100 meters. Therefore, the correct option is D) 100 m.