Question

In order to access the outer part of a terminal at an​ airport, you must walk quite some distance in a tunnel that travels under part of the airport. To make the walk less​ difficult, there is a moving walkway that travels at 2 feet per second. Suppose that Hana can travel 108 feet while walking on the walkway in the same amount of time it takes her to travel 48 feet while walking on the pavement without the aid of the moving sidewalk. How fast does Hana​ walk?

Answer 1

Hana walks at a speed of 8/9 feet per second.

Step-by-step explanation:

To find Hana's walking speed, we can set up a ratio using the distances she travels on the walkway and on the pavement. Let's call her walking speed 'v'.

On the walkway, Hana travels 108 feet at a speed of 2 feet per second. So the time it takes her to travel this distance is 108/2 = 54 seconds.

On the pavement, Hana travels 48 feet at a speed of 'v' feet per second. So the time it takes her to travel this distance is 48/v seconds.

Since both times are equal, we can set up the following equation: 54 = 48/v.

To solve for v, we can cross multiply and simplify: 54v = 48. This gives us v = 48/54 = 8/9.

Therefore, Hana walks at a speed of 8/9 feet per second.