Question

Cass Fitness sells gym passes in packs of 14. A competing gym, Wayne Wellness, sells gym passes in sets of 20. If both sold the same number of gym passes last month, what is the smallest number of passes each could have sold?

A. 280 passes

B. 560 passes

C. 140 passes

D. 420 passes

Answer 1

To find the smallest number of passes each gym could have sold, we need to find the least common multiple (LCM) of 14 and 20. The LCM of two numbers is the smallest multiple that is divisible by both numbers.

Step-by-step explanation:

To find the smallest number of passes each gym could have sold, we need to find the least common multiple (LCM) of 14 and 20. The LCM of two numbers is the smallest multiple that is divisible by both numbers.

Prime factorizing 14, we get 2 x 7. Prime factorizing 20, we get 2 x 2 x 5. To find the LCM, we take the highest power of each prime factor: 2 x 2 x 5 x 7 = 140. Therefore, the smallest number of passes each gym could have sold is 140 passes.