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Calculate the volume in liters of an 8.98 x 10⁻³ M silver(II) oxide solution that contains 500 mg of silver(II) oxide (AgO). Round your answer to 3 significant digits.

a) 5.56 L

b) 4.89 L

c) 2.23 L

d) 7.78 L

1 Answer

3 votes

Final answer:

The volume of the silver(II) oxide solution is 4.14 L.

Step-by-step explanation:

To calculate the volume in liters of the silver(II) oxide solution, we need to use the relationship between molarity, volume, and amount of solute. First, we convert the mass of silver(II) oxide to moles:

Mass of AgO = 500 mg = 0.5 g

Molar mass of AgO = 123.87 g/mol

Number of moles of AgO = 0.5 g / 123.87 g/mol

Next, we can use the given molarity to find the volume:

Molarity = 8.98 x 10^-3 M

Number of moles of AgO = Molarity x Volume

0.5 g / 123.87 g/mol = (8.98 x 10^-3 M) x Volume

Volume = 0.5 g / (8.98 x 10^-3 M x 123.87 g/mol)

Volume = 4.141 L

Rounded to 3 significant digits, the volume is 4.14 L.

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