Question

Write an equation of the line, in point-slope form, that passes through the two given points points: (-2, 10), (10,- 14)

a)y-2=-(x+10)
b)y-10 =(x+2)
c)y-10= –2(+2)
d) y-2 = -2(x - 10)

Answer 1

The equation of the line in point-slope form that passes through the points (-2, 10) and (10, -14) is y = -2x + 6.

Step-by-step explanation:

The point-slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) are the coordinates of a point on the line and m is the slope of the line. To find the equation of the line passing through (-2, 10) and (10, -14), we first need to find the slope.

Slope (m) = (change in y) / (change in x)

Let's calculate the slope using the given coordinates.

Slope = (-14 - 10) / (10 - (-2)) = -24 / 12 = -2

Now, we can choose one of the given points and substitute the values into the point-slope form equation.

Let's use the point (-2, 10):

y - 10 = -2(x - (-2))

y - 10 = -2(x + 2)

y - 10 = -2x - 4

y = -2x + 6

Therefore, the equation of the line in point-slope form is y = -2x + 6.