Final answer:
The probabilities for the three parts of the question are approximately 0.698 for no accidents over 7 days, 0.090 for exactly 2 accidents in September, and approximately 0.327 for no accidents during the next 4 days but at least one by the end of the 10th day. Option iii) is correct for both part A and B, but part C does not match any of the provided options.
Step-by-step explanation:
To solve the student's question, we will use the rules of probability for independent events. Let's address each part of the question:
Part A (Probability for 7 consecutive days)
The probability of no accidents at the intersection for 7 consecutive days is the product of the daily probabilities since the days are independent events. Therefore, the calculation is:
(0.95)^7 = 0.6983
The probability is approximately 0.698 which corresponds to answer iii).
Part B (Exactly 2 days with accidents in September)
September typically has 30 days. We use the binomial probability formula for exactly 2 days with accidents, which is:
P(X = 2) = C(30, 2) * (0.05)^2 * (0.95)^28
After calculating, we get an approximate probability of 0.090, which corresponds to answer iii).
Part C (No accident for next 4 days but at least one by the 10th day)
The probability of having no accidents for the next 4 days is simply:
(0.95)^4 = 0.8145
To ensure at least one accident by the 10th day, we subtract the probability of no accidents for 10 days from 1:
1 - (0.95)^10 = 0.4013
Now, multiplying these probabilities gives us the final answer:
(0.8145) * (0.4013) = 0.327
However, this scenario is not represented by the provided options, indicating a possible error in the question or the need for further clarification.