Question

You have one type of chocolate that sells for $2.30/Lb and another type of chocolate that sells for $8.10/lb. You would like to have 40.6 lbs of a chocolate mixture that sells for $6.40/Lb. How much of each chocolate will you need to obtain the desired mixture?

You will need

A) 15.4 lbs of the cheaper chocolate and 25.2 lbs of the expensive chocolate.
B) 20.8 lbs of the cheaper chocolate and 19.8 lbs of the expensive chocolate.
C) 12.6 lbs of the cheaper chocolate and 28 lbs of the expensive chocolate.
D) 18.2 lbs of the cheaper chocolate and 22.4 lbs of the expensive chocolate.

Answer 1

To obtain a mixture of 40.6 lbs of chocolate that sells for $6.40/lb, you can use a system of equations. The correct answer is A) 15.4 lbs of the cheaper chocolate and 25.2 lbs of the expensive chocolate.

Step-by-step explanation:

To obtain a mixture of 40.6 lbs of chocolate that sells for $6.40/lb, you can use a system of equations. Let x represent the amount of the cheaper chocolate and y represent the amount of the expensive chocolate. The first equation is x + y = 40.6, representing the total weight of the mixture. The second equation is (2.30 * x) + (8.10 * y) = 6.40 * 40.6, representing the total cost of the mixture. Solve this system of equations to find the values of x and y. The correct answer is A) 15.4 lbs of the cheaper chocolate and 25.2 lbs of the expensive chocolate.