87.0k views
2 votes
If three forces (2N, 3N, and 4N) act simultaneously on a 2kg body in equilibrium and the 3N force is removed, what will be the acceleration of the body?

User Ross Moody
by
7.5k points

1 Answer

5 votes

Final answer:

The acceleration of the body after removing the 3N force is 3 m/s².

Step-by-step explanation:

To find the acceleration of the body after removing the 3N force, we need to calculate the net force acting on the body. Since the body is in equilibrium before the force is removed, the net force is zero. Therefore, the sum of the remaining forces must be equal to the force that was removed.



So, the net force after removing the 3N force is 2N + 4N = 6N. To find the acceleration, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). Rearranging the equation, we can solve for acceleration: a = F/m. Plugging in the values, we get a = 6N/2kg = 3 m/s².

User ZMabrook
by
9.1k points