Final answer:
To find the moles of O₂ required to react with 32.5 moles of methanol, a balanced chemical equation of the combustion of methanol is used. The calculation reveals that 48.8 moles of O₂ are required.
Step-by-step explanation:
The inquiry asks how many moles of O₂ are necessary to react with 32.5 moles of methanol (CH₃OH). To answer this, we need a balanced chemical reaction. Methanol combustion is represented by:
2 CH₃OH + 3 O₂ → 2 CO₂ + 4 H₂O
This equation shows that 2 moles of methanol react with 3 moles of oxygen. Therefore, to find the amount of oxygen needed for 32.5 moles of methanol, we can set up a proportion:
(3 moles O₂ / 2 moles CH₃OH) = (x moles O₂ / 32.5 moles CH₃OH)
By cross-multiplication, we get:
x = (32.5 moles CH₃OH * 3 moles O₂) / 2 moles CH₃OH
x = 48.75 moles O₂
However, since the options given do not contain 48.75, we'll look for the closest value, which is 48.8 mol O₂ (option b).