Final answer:
The y-component of the ball's velocity just before it strikes the ground is 32.83 m/s, and the x-component of its velocity is 31.04 m/s.
Step-by-step explanation:
To find the y-component of the ball's velocity just before it strikes the ground, we need to determine the time it takes for the ball to reach the ground. We can use the equation h = 1/2gt^2, where h is the height of the building (42.2 m) and g is the acceleration due to gravity (9.8 m/s^2). Solving for t, we get t = sqrt(2h/g) = sqrt(2*42.2/9.8) s = 3.35 s. The y-component of the velocity is given by v_y = gt, so v_y = 9.8 * 3.35 = 32.83 m/s.
The x-component of the velocity can be determined using the equation d = v_x * t, where d is the horizontal distance traveled (104 m) and t is the time. Rearranging the equation, we get v_x = d / t = 104 / 3.35 = 31.04 m/s.