Question

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

a. 5 days.
b, 4 days.
c. 6 days.
d. 7 days.

Answer 1

To solve the problem, we need to determine the rate at which each man and each boy can complete the work. We then use these rates to find the time taken by 15 men and 20 boys to complete the work.

Step-by-step explanation:

To solve this problem, we need to determine the rate at which each man and each boy can complete the work. Let's assume that the rate of work for each man is 'm' and the rate of work for each boy is 'b'.

From the given information, we can set up the following equations:

6m + 8b = 1/10 (equation 1)

26m + 48b = 1/2 (equation 2)

Solving these two equations simultaneously, we can find the values of 'm' and 'b'.

Once we have the values of 'm' and 'b', we can calculate the time taken by 15 men and 20 boys to complete the work using the equation:

15m + 20b = t

Substituting the values of 'm' and 'b' we found earlier, we can solve for 't'.

Therefore, the time taken by 15 men and 20 boys to complete the work will be the value of 't'.