Question

A projectile is propelled along the x-axis. During 5.6 s it moves from position 66 m to position −37 m. Find its average velocity (including the sign).

a) 18.93 m/s
b) -18.93 m/s
c) 16.25 m/s
d) -16.25 m/s

Answer 1

The average velocity of the projectile is approximately -18.39 m/s.

Step-by-step explanation:

To find the average velocity of the projectile, we need to calculate the displacement and time interval.

The displacement (change in position) is given by:

displacement = final position - initial position = -37 m - 66 m = -103 m

The time interval is given as 5.6 s.

The average velocity is calculated by dividing the displacement by the time interval:

average velocity = displacement / time interval = -103 m / 5.6 s ≈ -18.39 m/s

Therefore, the average velocity (including the sign) is approximately -18.39 m/s.