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An apple falls out of a tree and takes 1.85 seconds to strike the ground. How fast was the mango going when it hit the ground?​

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Final answer:

To find the final velocity of the apple when it hit the ground, we use the equation v = u + at, plugging in the initial velocity (u) of 0 m/s, acceleration (a) of 9.8 m/s² due to gravity, and time (t) of 1.85 seconds to calculate a final velocity (v) of 18.13 m/s.

Step-by-step explanation:

To calculate how fast the apple was going when it hit the ground, we can use the kinematic equation for velocity under constant acceleration:

v = u + at

Where:

  • v is the final velocity
  • u is the initial velocity (which is 0 m/s since the apple fell from rest)
  • a is the acceleration due to gravity (which is 9.8 m/s²)
  • t is the time taken to fall (which is 1.85 seconds)

Plugging in the values:

v = 0 m/s + (9.8 m/s² * 1.85 s)

v = 18.13 m/s

So, the apple was going 18.13 m/s when it hit the ground.

User Jf Beaulac
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