Question

A Clydesdale drinks about 120 gallons of water every 4 days. At this rate, about how many gallons of water does a Clydesdale drink in 28 days?

a) 210 gallons
b) 240 gallons
c) 280 gallons
d) 300 gallons

Answer 1

c) 280 gallons

Step-by-step explanation:

The rate is 120 gallons every 4 days. Therefore, the Clydesdale's daily rate is 120/4 = 30 gallons.

Now, you can find the amount of water consumed in 28 days:

Water in 28 days = Daily rate × Number of days

Water in 28 days = 30 gallons/day × 28 days

Water in 28 days = 840 gallons

The closest option is:

c) 280 gallons

Answer 2

To find out how many gallons of water a Clydesdale drinks in 28 days, we can multiply the amount consumed in one 4-day period by the number of periods.

Step-by-step explanation:

To find out how many gallons of water a Clydesdale drinks in 28 days, we need to find out how many 4-day periods are in 28 days. Since 28 days divided by 4 days equals 7, there are 7 periods of 4 days in 28 days. Now, to find the total amount of water consumed in 28 days, we can multiply the amount consumed in one 4-day period by the number of periods. So, 120 gallons multiplied by 7 equals 840 gallons. Therefore, a Clydesdale drinks about 840 gallons of water in 28 days.