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Find all values of k for which the quadratic equation has one real solution:

2x² + Tx + k = 0

Write your answer as an equality or inequality in terms of k.

User Ed Summers
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1 Answer

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Final answer:

To find the values of k for which the quadratic equation has one real solution, consider the discriminant of the quadratic equation and set it equal to zero. The values of k can be expressed as the inequality k ≤ T²/8.

Step-by-step explanation:

To find the values of k for which the quadratic equation has one real solution, we need to consider the discriminant of the quadratic equation. The discriminant is the expression b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0. In this case, the equation is 2x² + Tx + k = 0, so the discriminant is T² - 4(2)(k).

A quadratic equation has one real solution when the discriminant is equal to zero, so we set the discriminant equal to zero and solve for T: T² - 4(2)(k) = 0.

The solution is: T² = 8k. Therefore, the values of k for which the quadratic equation has one real solution can be expressed as the inequality k ≤ T²/8.

User VuVirt
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