Final answer:
A one-sample t-test is used to determine if the response time for senior citizens is longer than that for non-seniors. With a sample mean response time of 12 minutes and a standard deviation of 6 minutes for a sample of 100 senior citizens, the t-score calculation indicates a rejection of the null hypothesis at the 95% confidence interval.
Step-by-step explanation:
To determine if the response time to emergency calls from senior citizens is significantly longer than the response time to those from non-senior patients, we can use a one-sample t-test for the mean. We are comparing the sample mean response time for senior citizens (12 minutes) to a known population mean (10 minutes). The hypothesis tested is:
H0: μ = 10 (The mean response time for senior citizens is the same as non-seniors)
HA: μ > 10 (The mean response time for senior citizens is greater than non-seniors)
With a standard deviation of 6 minutes and a sample size of 100, the standard error (SE) is calculated as SE = 6 / √100 = 0.6. To calculate the t-score, we use the formula: t = (Sample Mean - Population Mean) / SE, giving us t = (12 - 10) / 0.6 = 3.33. We then compare the calculated t-score to the critical t-value from the t-distribution table at the 95% confidence interval (CI) for 99 degrees of freedom (since sample size - 1 = 100 - 1 = 99). If the calculated t-score exceeds the critical value, we reject the null hypothesis. In this case, the critical t-value is approximately 1.66. Since our t-score is greater than the critical value, we reject the null hypothesis and conclude that there is evidence at the 95% confidence level to support that the mean response time to emergency calls from senior citizens is longer than for non-senior patients.