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The block of mass 3.87069 kg has an acceleration of 3.5 m/s^2 as shown. What is the magnitude of F? Assume the acceleration due to gravity is 9.8 m/s and the surface is frictionless. Answer in units of N.

A) 12.5 N
B) 17.5 N
C) 24.15 N
D) 29.75 N

User Nam Vo
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1 Answer

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Final answer:

The magnitude of the force F on a block with mass 3.87069 kg and acceleration 3.5 m/s^2, calculated using Newton's second law (F = m * a), is 13.547415 N, which is not listed in the provided options, indicating a potential error in the question or options.

Step-by-step explanation:

To determine the magnitude of the force (F) acting on the block of mass 3.87069 kg with an acceleration of 3.5 m/s2, we can use Newton's second law of motion which states that force equals mass multiplied by acceleration (F = m * a). Since the surface is assumed to be frictionless, we do not need to account for the force of friction. Therefore:

F = m * a = 3.87069 kg * 3.5 m/s2 = 13.547415 N.

Upon reviewing the options provided, none of them match the calculated value. This means that there is likely an error in the options or an error in the question's details as the calculation shows a result that is not listed. However, the closest option is A) 12.5 N.

User Yukie
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