Question

Given that the actual density of iron is 7.90 g / cubic cm, what would be the mass of a piece of iron that occupies 17.9 cubic cm?

A) 141.10 g
B) 69.20 g
C) 56.11 g
D) 34.55 g

Answer 1

The mass of the piece of iron that occupies 17.9 cm³ is 141.10 g.

Step-by-step explanation:

The mass of an object can be calculated by multiplying its density by its volume. In this case, the actual density of iron is given as 7.90 g/cm³. The volume of the piece of iron is 17.9 cm³. So, to find the mass, we can use the formula:

Mass = Density x Volume

Substituting the values, we get:
Mass = 7.90 g/cm³ x 17.9 cm³
Simplifying, we get:
Mass = 141.10 g

Therefore, the mass of the piece of iron that occupies 17.9 cm³ is 141.10 g.