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Find the period of the function y = 3∕2 tan(1∕3x).
A) π∕3
B) 3π
C) π
D) π∕6

1 Answer

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Final answer:

The period of the function y = 3/2 tan(1/3x) is found by dividing π by the coefficient of x in the tangent function, which gives 3π as the correct period.

Step-by-step explanation:

The period of a tangent function like y = a tan(bx) can be found by using the period formula for tangent, which is π/b. In the given function y = 3/2 tan(1/3x), the coefficient b in front of x is 1/3. Therefore, we can find the period by taking π and dividing it by 1/3, which equals 3π. This gives us option B) 3π as the correct period of the given tangent function.

User Stephen Hazel
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