Final answer:
For the provided sets of quantum numbers, A) n = 2, l = 0, mᶻ = 0, mₗ = 0, B) n = 2, l = 1, mᶻ = 0, mₗ = 0, C) n = 2, l = 1, mᶻ = 1, mₗ = -1 are possible combinations, while D) n = 2, l = 2, mᶻ = -1, mₗ = 0 is not possible.
Step-by-step explanation:
For the provided sets of quantum numbers, the possible combinations are as follows:
A) n = 2, l = 0, m᷃ = 0, mₕ = 0: This set of quantum numbers is possible with one electron in the 2s orbital.
B) n = 2, l = 1, m᷃ = 0, mₕ = 0: This set of quantum numbers is possible with one electron in the 2px, 2py, or 2pz orbital.
C) n = 2, l = 1, m᷃ = 1, mₕ = -1: This set of quantum numbers is possible with one electron in the 2px orbital.
D) n = 2, l = 2, m᷃ = -1, mₕ = 0: This set of quantum numbers is not possible because the value of l cannot exceed n-1, which in this case would be 1.