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What is the difference between the expressions (-6s^2+12s-8) and (3s^2+8s-6)?

A) -9s^2 + 4s - 2
B) -3s^2 + 4s - 2
C) -3s^2 + 20s - 2
D) -9s^2 + 20s - 2

1 Answer

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Final answer:

The difference between the expressions (-6s^2+12s-8) and (3s^2+8s-6) is -9s^2 + 20s - 2.

Step-by-step explanation:

The difference between the expressions (-6s^2+12s-8) and (3s^2+8s-6) is (-9s^2 + 20s - 2).

To find the difference, subtract the coefficients of each term. The coefficient of s^2 is -6 - 3 = -9. The coefficient of s is 12 - 8 = 4. The constant terms are -8 - (-6) = -2.

Combining the coefficients, we get -9s^2 + 4s - 2. Therefore, the correct answer is option D) -9s^2 + 20s - 2.

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