Question

You need to make an aqueous solution of 0.183 M potassium sulfate for an experiment in lab, using a 500 mL volumetric flask. How much solid potassium sulfate should you add?

a. 4.575 grams
b. 9.15 grams
c. 18.3 grams
d. 36.6 grams

Answer 1

To make a 0.183 M aqueous solution of potassium sulfate using a 500 mL volumetric flask, you need to add approximately 16.0 grams of solid potassium sulfate.

Step-by-step explanation:

To calculate the amount of solid potassium sulfate needed to make a 0.183 M aqueous solution, we can use the relationship between moles, concentration, and volume.

Now the formula used for calculating moles is Moles = Concentration x Volume.

Given: concentration = 0.183 M and volume = 0.5 L,

Moles = 0.183 M x 0.5 L = 0.0915 mol.

Potassium sulfate has a molar mass of 174.2592 g/mol.

Mass = moles x molar mass = 0.0915 mol x 174.2592 g/mol = 15.96532 g.

Rounding to three significant figures, the solid potassium sulfate needed is approximately 16.0 grams.