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The sides of a nuclear power plant cooling tower form a hyperbola. the diameter of the bottom of the tower is 314 feet. the smallest diameter of the tower is 206 feet which is 393 feet above the ground. the tower is 578 feet tall. find the width of the tower at a height of 72 feet. round to the nearest integer.

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Final Answer:

The width of the tower at a height of 72 feet is approximately 247 feet.

Step-by-step explanation:

Define the given information:

Bottom diameter (d_b) = 314 feet

Smallest diameter (d_s) = 206 feet

Height of smallest diameter (h_s) = 393 feet

Total height (h_t) = 578 feet

Desired height (h_d) = 72 feet

Formulate the equation for the hyperbola:

We can use the standard equation for a horizontal hyperbola with center at (0,0):

(y-0)^2 / a^2 - (x-0)^2 / b^2 = 1

where:

a is the vertical distance from the center to a focus

b is the horizontal distance from the center to a vertex

Relate the given information to the equation:

The bottom diameter corresponds to the width of the tower at ground level (y = 0). Therefore, the bottom diameter is equal to 2b.

The smallest diameter corresponds to the width of the tower at a height of 393 feet (y = 393). Therefore, the smallest diameter is equal to 2b - 2a.

Solve for the parameters:

Substitute the given values:

2b = 314 feet

2b - 2a = 206 feet

Solve for a and b:

a = 54 feet

b = 157 feet

Find the width at the desired height:

Substitute the desired height (h_d = 72 feet) into the equation:

(72-0)^2 / 54^2 - (x-0)^2 / 157^2 = 1

Solve for x:

x ≈ 126 feet

Therefore, the width of the tower at a height of 72 feet is approximately 126 feet * 2 = 247 feet.

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