Final answer:
One mole of magnesium nitrate, Mg(NO3)2, contains 1 mole of Mg2+ ions and 2 moles of NO3- ions, totaling 3 moles or 1.8066 × 10^24 ions.
Step-by-step explanation:
The student asked for the total number of ions in one mole of magnesium nitrate, Mg(NO3)2. First, it's important to recognize what constitutes magnesium nitrate. Magnesium nitrate contains a magnesium cation, Mg2+, and two nitrate anions, NO3−. For every formula unit of Mg(NO3)2, there is one Mg2+ ion and two NO3− ions. Therefore, one mole of magnesium nitrate will have 1 mole of Mg2+ ions and 2 moles of NO3− ions. Given that 1 mole equals 6.022 × 1023 entities (Avogadro's number), we can calculate the total number of ions as follows:
- 1 mole of Mg2+ is 6.022 × 1023 Mg2+ ions.
- 2 moles of NO3− is 2 × 6.022 × 1023 NO3− ions.
- Thus, the total number of ions in one mole of Mg(NO3)2 is 3 moles of ions, which equals 3 × 6.022 × 1023 ions.
In conclusion, one mole of magnesium nitrate contains 3 moles of ions or 1.8066 × 1024 ions in total.