Final answer:
The Ksp for AgCl can be calculated using its molar solubility. In this case, the solubility of AgCl in water at 25°C is 1.33 × 10¯^5 M, so the Ksp for AgCl is 1.77 × 10¯^10.
Step-by-step explanation:
The molar solubility of a compound can be used to calculate its Ksp value. In this case, the solubility of AgCl in water at 25°C is 1.33 × 10¯^5 M. The Ksp expression for AgCl is [Ag+][Cl-] = x², where x is the molar solubility. Therefore, the Ksp for AgCl is 1.33 × 10¯^5 * 1.33 × 10¯^5 = 1.77 × 10¯^10.