Final answer:
The zeroes of the equation x² - 4x + 5 = 0 do not exist in the realm of real numbers.
Step-by-step explanation:
The quadratic formula can be used to find the zeroes of a quadratic equation of the form ax² + bx + c = 0. For the equation x² - 4x + 5 = 0, we can identify the values of a, b, and c as 1, -4, and 5 respectively. Plugging these values into the quadratic formula gives us:
x = (-b ± √(b² - 4ac))/(2a)
= (-(-4) ± √((-4)² - 4(1)(5)))/(2(1))
= (4 ± √(16-20))/2
= (4 ± √(-4))/2
Since there is a negative under the square root, we cannot take the square root of a negative number in the realm of real numbers. Therefore, there are no real roots for the equation x² - 4x + 5 = 0.