Question

The ph of a solution obtained by dissolving 5 x 10-4 moles of ca(oh)2 (strong electrolyte) to 100 ml solution at 298 k will be

Answer 1

To find the pH of the solution obtained by dissolving 5 x 10-4 moles of Ca(OH)2 to 100 ml solution, you will need to determine the concentration of hydroxide ions [OH-] in the solution and use the Kw expression to calculate the pOH.

Step-by-step explanation:

We begin by determining [OH-]. The concentration of the solute is 0.0044 M, but because Ca(OH)₂ is a strong base, there are two OH ions in solution for every formula unit dissolved, so the actual [OH-] is two times this: [OH-] = 2 × 0.0044 M = 0.0088 M.

Now we can use the Kw expression to calculate the pOH. Kw = [H+] x [OH-] = (1.0 × 10-14)