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The heat of combustion for n–heptane, c7h16 c 7 h 16 , is 4817 kj/mol. how much heat is released if 998 kg of this liquid burns completely?

User Loukas
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1 Answer

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Final answer:

Approximately 47,971,216 kJ of heat is released when 998 kg of n-heptane burns completely.

Step-by-step explanation:

The heat of combustion for n-heptane (C7H16) is 4817 kJ/mol. To calculate the amount of heat released when 998 kg of n-heptane burns completely, we need to convert the mass of n-heptane to moles using its molar mass. The molar mass of n-heptane is calculated by adding up the atomic masses of its constituent elements: (7 x 12.01) + (16 x 1.01) = 100.21 g/mol. Therefore, 998 kg of n-heptane is equal to 998,000 g, which is 9955.2 moles.

To find the heat released, we can use the given heat of combustion, which is 4817 kJ/mol. We multiply this value by the number of moles of n-heptane: 4817 kJ/mol x 9955.2 mol = 47,971,216 kJ.

Therefore, when 998 kg of n-heptane burns completely, approximately 47,971,216 kJ of heat is released.

User Zzztimbo
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