Question

The initial velocity of a body is 5.20 m/s. what is its velocity after 2.50 s (a) if it accelerates uniformly at 3.00 m/s2 and (b) if it accelerates uniformly at - 3.00 m/s2 ?

Answer 1

The kinematic equation that relates initial velocity (u), time (t), acceleration (a), and final velocity (v) is given by: v = u + at. after 2.50 seconds, the velocity is 12.70 m/s if it accelerates uniformly at 3.00 m/s² and -2.30 m/s if it accelerates uniformly at -3.00 m/s².

Step-by-step explanation:

The kinematic equation that relates initial velocity (u), time (t), acceleration (a), and final velocity (v) is given by:

v = u + at

where:

- u is the initial velocity,

-t is the time,

- a is the acceleration,

- v is the final velocity.

Let's use this formula to calculate the final velocities after 2.50 seconds for the given scenarios.

(a) If it accelerates uniformly at 3.00 m/s²:

v = 5.20 m/s + (3.00 m/s²)(2.50 s)

v = 5.20 m/s + 7.50 m/s

v = 12.70 m/s

(b) If it accelerates uniformly at -3.00 m/s²:

v = 5.20 m/s + (-3.00 m/s²)(2.50 s)

v = 5.20 m/s - 7.50 m/s

v = -2.30 m/s

Therefore, after 2.50 seconds, the velocity is:

(a) 12.70 m/s if it accelerates uniformly at 3.00 m/s²,

(b) -2.30 m/s if it accelerates uniformly at -3.00 m/s².