Final Answer:
The magnitudes of the forces exerted by the ground are:
(a) The force exerted by the ground on the front wheels of the truck is 44,100 N.
(b) The force exerted by the ground on the rear wheels of the truck is also 44,100 N.
Step-by-step explanation:
To determine the forces exerted by the ground on the front and rear wheels, we can use the concept of weight and the distribution of the truck's mass. The weight (W) is given by the formula W = m * g, where m is the mass and g is the acceleration due to gravity. In this case, the total weight of the truck and its contents is 9,000 kg * 9.8 m/s² = 88,200 N.
(a) The force exerted by the ground on the front wheels is equal to the weight distributed over the front axle. If the truck is evenly loaded, the front and rear axles each bear half of the weight. Therefore, the force on the front wheels is 1/2 * 88,200 N = 44,100 N.
(b) Similarly, the force exerted by the ground on the rear wheels is equal to the weight distributed over the rear axle. In an even distribution scenario, the force on the rear wheels is also 1/2 * 88,200 N = 44,100 N.
In summary, both the front and rear wheels experience equal forces of 44,100 N, and the total weight is evenly distributed between them. This assumes a balanced load, and actual forces could vary based on the distribution of the truck's contents.