Question

The excess gibbs free energy of a binary liquid mixture at t and p is given by: T = (−2.6 x1 − 1.8x2)x1x2 , a) find expression of ln 1 and ln 2 at t and p. b) show that when these expressions are combined in accordance with equation

Answer 1

The expressions for ln γ1 and ln γ2 are derived from the excess Gibbs free energy equation for a binary liquid mixture. Part b) of the question cannot be completed without further information on the specific equation that combines these values.

Step-by-step explanation:

The question deals with calculating the activity coefficients (γ1 and γ2) in a binary liquid mixture using the excess Gibbs free energy at temperature (t) and pressure (p). The express for the excess Gibbs free energy (Gexcess) is given as Gexcess = (−2.6 x1 − 1.8x2)x1x2, where x1 and x2 are the mole fractions of the two components.

Part a) of the question asks to find expressions for ln γ1 and ln γ2, which can be derived using the relation γ=e(∆Gexcess/(RT)). By substituting the known values of Gexcess into this equation, we can obtain the expressions for ln γ1 and ln γ2.

Part b) mentions an unspecified equation that combines ln γ1 and ln γ2. Without the specific equation, this part cannot be completed accurately, but would presumably involve ensuring that the relationship between ln γ1 and ln γ2 is consistent with the properties of non-ideal mixtures, possibly involving Raoult's law or another similar thermodynamic principle.