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The captain orders his starship to accelerate from rest at a rate of "1 g" (1 g = 9.8 m/s²). How many days does it take the starship to reach 75% the speed of light?

A. 3.85 days
B. 4.23 days
C. 5.46 days
D. 6.13 days

1 Answer

2 votes

Final answer:

To calculate the days it would take a starship to accelerate to 75% the speed of light at 1g, a simple kinematic equation yields 265.79 days. However, this does not consider relativistic effects like time dilation that become significant at such high speeds, rendering this answer incorrect in the context of relativistic physics. A different, relativistic approach is required for this problem.

Step-by-step explanation:

This asks how many days it would take for a starship to accelerate from rest to reach 75% the speed of light (0.75c), assuming a constant acceleration of 1g, which is equivalent to 9.8 m/s². To find this, we use the formula: time = (final velocity - initial velocity) / acceleration. Considering that the speed of light (c) is approximately 3 x 10⁸ m/s, 75% of that speed is 2.25 x 10⁸ m/s. By rearranging the formula for time, we get time = (2.25 x 10⁸ m/s) / (9.8 m/s²) = 2.29591837 x 10⁷ seconds. Converting this time into days: (2.29591837 x 10⁷ seconds) / (3600 seconds/hour) / (24 hours/day) = 265.79 days. However, since none of the provided options matches the calculated time, it must be considered that relativistic effects are not accounted for in this calculation. In reality, relativistic effects would significantly change the time needed as the spacecraft approaches the speed of light, and this formula does not apply. Therefore, a relativistic formula should be used instead to account for time dilation.

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