Final answer:
Assuming there is a typo in the equation provided by the student, the solution process for a simple linear equation was demonstrated. Nevertheless, without the correct equation, we cannot provide an accurate solution. The student may need to clarify the correct form of the equation for a precise answer.
Step-by-step explanation:
To solve the equation presented in the question, there appears to be a typo in the original equation provided by the student. Assuming the equation is meant to be a simple linear equation that can be solved for z, the equation should take a form similar to az = b, where a and b are constants and z is the variable we want to solve for.
For example, if the correct equation was z + 2 = 4 - 45, simplifying the right side of the equation would give us z + 2 = -41. Solving for z would involve subtracting 2 from both sides, giving us z = -41 - 2, which results in z = -43.
However, without the correct equation, this is purely speculative. The student may need to provide the correct equation for an accurate solution. If the equation includes a typo and is a quadratic equation, the solution would involve using the quadratic formula z = (-b ± √(b² - 4ac)) / (2a), where a, b, and c are constants from the equation of the form at² + bt + c = 0.