Final answer:
To convert helium atoms to grams, divide the number of atoms by Avogadro's number to get moles, then multiply by the molar mass of helium. 7.32 × 1025 helium atoms equal 486.36 grams of helium.
Step-by-step explanation:
The student is asking about converting the number of helium atoms into grams. To find this, we need to use the concept of the mole, which is a basic unit in chemistry for quantifying the amount of a substance. The conversion factor from moles to atoms is Avogadro's number, which is approximately 6.02 × 1023 atoms/mole. This allows us to convert between moles and the number of atoms.
To convert atoms to moles, divide the number of atoms by Avogadro's number. If we have 7.32 × 1025 helium atoms, we would calculate the number of moles and then the mass:
- Divide the number of helium atoms by Avogadro's number: 7.32 × 1025 atoms ÷ 6.02 × 1023 atoms/mole = 121.59 moles of helium.
- To find the mass, multiply the moles by the molar mass of helium, which is 4.00 grams/mole: 121.59 moles × 4.00 g/mole = 486.36 grams of helium.