Final answer:
27.0g of Aluminium contains 6.022\u00d710\u00b2\u00b3 aluminium atoms, as it equals to 1 mole of Aluminium based on its atomic weight.
Step-by-step explanation:
You want to know how many atoms are in 27.0g of Aluminium, given that Aluminium's atomic weight is 27 and 32.0g of sulphur contains 6.02\u00d710\u00b2\u00b3 sulphur atoms.
To find the number of atoms in 27.0g of Aluminium, you divide the mass of Aluminium by its atomic weight to find the number of moles, and then multiply by Avogadro's number (6.022\u00d710\u00b2\u00b3 atoms/mol). Since the atomic weight of Aluminum is 27, this means there is 1 mole of Aluminum in 27g, which is Avogadro's number of atoms.
Therefore, 27.0g of Aluminium contains 6.022\u00d710\u00b2\u00b3 aluminium atoms.