Question

HT bisects SR at point H. If SH = (x² + 6x - 28) and HR = (4x + 20), find SR.

A) SR = x² + 10x - 8
B) SR = 5x² + 26x - 48
C) SR = 4x² + 26x - 8
D) SR = x² + 26x + 20
E) SR = 4x² + 10x - 48

Answer 1

To find SR, add SH and HR to get SR = x² + 10x - 8.

Step-by-step explanation:

To find SR, we need to add SH and HR. Thus, SR = SH + HR.

SR = (x² + 6x - 28) + (4x + 20)

SR = x² + 6x - 28 + 4x + 20

Combining like terms, SR = x² + 10x - 8

Therefore, the correct answer is A) SR = x² + 10x - 8.