153k views
4 votes
The temperature of a sample of water increases by 70.2 °C when 24,500 J are applied. The specific heat of water is 4.18 J/g °C. What is the mass of the sample of water?

a) 135.4 g
b) 348.8 g
c) 583.7 g
d) 946.2 g

1 Answer

7 votes

Final answer:

To find the mass of the water sample, the formula q = mcΔT is used, where q is the heat added and c is the specific heat capacity of water. The calculation yields a mass of 83.8 g, which does not match any of the provided answer options, indicating a possible discrepancy in the question.

Step-by-step explanation:

To determine the mass of the water sample from the information provided in the question, we can use the formula for heat transfer, q = mcΔT, where q is the heat in joules, m is the mass in grams, ΔT is the change in temperature in degrees Celsius, and c is the specific heat capacity. Given that the water sample's temperature increases by 70.2 °C when 24,500 J of heat are added and the specific heat capacity of water is 4.18 J/g°C, we can rearrange the formula to solve for the mass. Solving the equation, we get m = q / (cΔT) = 24,500 J / (4.18 J/g°C × 70.2 °C) which gives us the mass of the water sample.

After performing the calculation, the mass of the water sample is found to be 83.8 g, which is not an option provided. Therefore, it appears there might be a discrepancy in the given choices or a mistake in the given data since none of the options match the calculated value.

User Izayoi Sakuya
by
7.8k points