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What is the sum of the first six terms of the geometric series 6, -18, 54, -162, ...?

A) 63
B) 729
C) -243
D) -567

User Itsme
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1 Answer

4 votes

Final answer:

The sum of the first six terms of the geometric series is calculated using the formula for the sum of a geometric series. After identifying the common ratio to be -3, the formula is applied to find the sum, which resulted in -364; however, this answer does not match the provided options.

Step-by-step explanation:

The question asks for the sum of the first six terms of a geometric series. A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio (r). To identify the common ratio for the series given (6, -18, 54, -162, ...), we divide the second term by the first term:

r = (-18) / 6 = -3.

Now, the sum Sn of the first n terms of a geometric series can be calculated using the formula

Sn = a(1 - rn) / (1 - r),

where a is the first term, r is the common ratio, and n is the number of terms. For the first six terms, we have:

a = 6, r = -3, n = 6.

Applying these values to the formula:

S6 = 6(1 - (-3)6) / (1 - (-3))

Simplifying further:

S6 = 6(1 - 729) / (1 + 3)

S6 = 6(-728) / 4

S6 = -1456 / 4

S6 = -364

However, none of the given options match this result, so it seems there may be an error either in the calculation or the options provided for the answer.

User Sthustfo
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