Question

The midpoint of AB is M(5,-2). If the coordinates of A are (6,-5), what are the coordinates of B

Answer 1

Mid point formula is

`\begin{gathered} (x,y)=((x_1+x_2)/(2),(y_(1+)y_2)/(2)) \\ (5,-2)=((6+x_2)/(2),(-5+y_2)/(2)) \end{gathered}`
`\begin{gathered} 5=(6+x_2)/(2) \\ 10=6+x_2 \\ 10-6=x_2 \\ 4=x_2 \end{gathered}`
`\begin{gathered} -2=(-5+y_2)/(2) \\ -4=-5+y_2 \\ -4+5=y_2 \\ 1=y_2 \end{gathered}`

Therefore the coordinates of B is (4,1)